To compare the functions \( f(x) = 8x \) and \( g(x) = \log_8(x) \), we should find some points on the graph of \( g(x) \).
First, let's derive a couple of points for \( g(x) \).
- Choose \( x = 1 \):
\[ g(1) = \log_8(1) \] Since any logarithm of 1 is 0, we have: \[ g(1) = 0 \]
So, one point on the graph of \( g(x) \) is \( (1, 0) \).
- Choose \( x = 8 \):
\[ g(8) = \log_8(8) \] Since \( 8^1 = 8 \), we have: \[ g(8) = 1 \]
So, another point on the graph of \( g(x) \) is \( (8, 1) \).
Now, we have two points on the graph of \( g(x) \):
- \( (1, 0) \)
- \( (8, 1) \)
Based on this comparison, we can conclude that the points \( (1, 0) \) and \( (8, 1) \) are two points on the graph of \( g(x) = \log_8(x) \).