Let's first rewrite both equations in slope-intercept form (y = mx + b) to compare their slopes and y-intercepts.
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For the first equation: \[ -\frac{1}{2}x + y = 8 \] We can isolate \(y\): \[ y = \frac{1}{2}x + 8 \] Here, the slope (m) is \(\frac{1}{2}\) and the y-intercept (b) is \(8\).
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For the second equation: \[ \frac{1}{2}y = \frac{1}{4}x - 4 \] Multiplying both sides by \(2\) to eliminate the fraction gives: \[ y = \frac{1}{2}x - 8 \] Here, the slope (m) is also \(\frac{1}{2}\) and the y-intercept (b) is \(-8\).
Now we can compare:
- Both equations have the same slope, which is \(\frac{1}{2}\).
- The y-intercepts are different: one is \(8\) and the other is \(-8\).
Based on this analysis, the correct response is:
The equations have the same slopes and are parallel lines.