To compare the initial values of Linear Function 1 and Linear Function 2, we can analyze each function.
Linear Function 1:
- Lionel’s cell phone plan costs $45 per month. This means that the total cost starts at $45 when \(x = 1\). However, if we consider \(x = 0\) (when he hasn't had the plan for any months), the cost is essentially $0. For each additional month, the cost increases by $45, but the initial value when \(x=0\) is $0.
Linear Function 2:
- The equation is given by \(y = 40x + 60\). Here, the initial value occurs when \(x = 0\). Substituting \(x = 0\) into the equation gives: \[ y = 40(0) + 60 = 60 \] Therefore, the initial value of Linear Function 2 is $60.
Now we can summarize the initial values:
- Linear Function 1: Initial value at \(x=0\) is $0.
- Linear Function 2: Initial value at \(x=0\) is $60.
Based on these calculations, the comparison yields the following conclusion:
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.
So the correct response is:
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.