To compare the initial values of the two linear functions, we need to identify the initial values based on the given information.
Linear Function 1 does not provide a variable, but we can interpret it as a flat rate:
- It costs $45 per month. Therefore, when \( x = 0 \) (initial month), the cost \( y \) is $45.
Linear Function 2 is given in the form of \( y = 40x + 60 \):
- Here, when \( x = 0 \), we substitute \( 0 \) for \( x \): \[ y = 40(0) + 60 = 60 \]
- Thus, the initial value for Linear Function 2 is $60.
Now we can summarize the initial values:
- Linear Function 1 initial value: $45
- Linear Function 2 initial value: $60
Comparing these two values:
- $45 (Linear Function 1) is less than $60 (Linear Function 2).
Therefore, Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.