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Compare Linear Function 1 with Linear Function 2. Which one has the lesser initial value? Linear Function 1: Lionel’s cell phon...Question
Compare Linear Function 1 with Linear Function 2. Which one has the lesser initial value?Linear Function 1: Lionel’s cell phone plan costs $45 per month.Linear Function 2: The relationship between the number of months Ruby has had her cell phone (x) and the total cost (y) is given by y=40x+60 .(1 point)ResponsesLinear Function 2 has the lesser initial value, with an initial value equal to $40 while Linear Function 1 has an initial value equal to $45.Linear Function 2 has the lesser initial value, with an initial value equal to $40 while Linear Function 1 has an initial value equal to $45.Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.
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GPT-4o mini
To compare the initial values of the two linear functions, we need to identify the initial values based on the given information.
**Linear Function 1** does not provide a variable, but we can interpret it as a flat rate:
- It costs $45 per month. Therefore, when \( x = 0 \) (initial month), the cost \( y \) is $45.
**Linear Function 2** is given in the form of \( y = 40x + 60 \):
- Here, when \( x = 0 \), we substitute \( 0 \) for \( x \):
\[ y = 40(0) + 60 = 60 \]
- Thus, the initial value for Linear Function 2 is $60.
Now we can summarize the initial values:
- Linear Function 1 initial value: $45
- Linear Function 2 initial value: $60
Comparing these two values:
- $45 (Linear Function 1) is less than $60 (Linear Function 2).
Therefore, **Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.**
**Linear Function 1** does not provide a variable, but we can interpret it as a flat rate:
- It costs $45 per month. Therefore, when \( x = 0 \) (initial month), the cost \( y \) is $45.
**Linear Function 2** is given in the form of \( y = 40x + 60 \):
- Here, when \( x = 0 \), we substitute \( 0 \) for \( x \):
\[ y = 40(0) + 60 = 60 \]
- Thus, the initial value for Linear Function 2 is $60.
Now we can summarize the initial values:
- Linear Function 1 initial value: $45
- Linear Function 2 initial value: $60
Comparing these two values:
- $45 (Linear Function 1) is less than $60 (Linear Function 2).
Therefore, **Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.**
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