To compare the initial values of Linear Function 1 and Linear Function 2, we need to identify the initial value (the y-intercept) of each function.
Linear Function 1: Taesha starts the year with $50 saved and saves an additional $25 a week. The equation can be represented as: \[ y = 25x + 50 \] Here, the initial value (when \( x = 0 \)) is \( y = 50 \).
Linear Function 2: The function is given by: \[ y = 37x + 40 \] Here, the initial value (when \( x = 0 \)) is \( y = 40 \).
Now we can compare the initial values:
- Initial value of Linear Function 1 is $50.
- Initial value of Linear Function 2 is $40.
Since \( 50 > 40 \), Linear Function 1 has the greater initial value.
So, the answer is 1.