To compare the initial values of the two linear functions:
Linear Function 1: Lionels's cell phone plan costs $45 per month. This implies that every month, regardless of the number of months, the cost will always start at $45.
Linear Function 2: The relationship is given by \( y = 40x + 60 \). To determine the initial value, we can substitute \( x = 0 \) (which represents the starting point when Ruby hasn't had her cell phone plan for any months yet):
- When \( x = 0 \): \[ y = 40(0) + 60 = 60 \]
So, the initial value of Linear Function 1 is $45, and the initial value of Linear Function 2 is $60.
Comparing these values, we find:
Linear Function 1 has the lesser initial value of $45, while Linear Function 2 has an initial value of $60.
Thus, the correct response is:
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.