To determine how many brochures need to be ordered for Company A to cost more than Company B, we can set up an inequality based on their costs.
Let \( b \) represent the number of brochures.
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The cost for Company A is: \[ \text{Cost}_A = 25 + 0.20b \]
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The cost for Company B is: \[ \text{Cost}_B = 0.30b \]
To find when Company A costs more than Company B, we set up the inequality: \[ 25 + 0.20b > 0.30b \]
Now, we can solve for \( b \):
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Subtract \( 0.20b \) from both sides: \[ 25 > 0.30b - 0.20b \] \[ 25 > 0.10b \]
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Now, divide both sides by \( 0.10 \): \[ \frac{25}{0.10} > b \] \[ 250 > b \]
This means that for \( b < 250 \), Company A costs more than Company B.
To find the number of brochures for Company A to cost more than Company B, \( b \) would need to be greater than 250:
Therefore, the correct conclusion is that Company A will cost more than Company B when \( b > 250 \).