Comment on the solubility of iodine (I2) in each of the following liquids. State whether at room temperature you expect I2 to be highly soluble or almost insoluble, and choose the appropriate reasons why.
HINT: It may behoove you to draw the Lewis structure for each molecule.
(A) I2 in CCl4(liquid):
- unanswered
highly soluble almost insoluble
Explain your answer from part (A) above. Check all that apply.
- unanswered
The components are both polar and therefore have the capability of mixing. The components are both polar and therefore they don't have the capability of mixing. The components are both nonpolar and therefore have the capability of mixing. The components are both nonpolar and therefore they don't have the capability of mixing. One component is polar and the other is nonpolar, and therefore they have the capability of mixing. One component is polar and the other is nonpolar, and therefore they don't have the capability of mixing. The components both have similar molecular weights and therefore have the capability of mixing. The components both have similar molecular weights and therefore they don't have the capability of mixing. One component has a much higher molecular weight than the other, and therefore they have the capability of mixing. One component has a much higher molecular weight than the other, and therefore they don't have the capability of mixing. The components are both liquid at room temperature and therefore have the capability of mixing. The components are both liquid at room temperature and therefore they don't have the capability of mixing. The components both lack hydrogen bonding, and therefore have the capability of mixing. The components both lack hydrogen bonding, and therefore they don't have the capability of mixing. One component has hydrogen bonding, while the other lacks it; therefore, they have the capability of mixing. One component has hydrogen bonding, while the other lacks it; therefore, they don't have the capability of mixing.
(B) I2 in HF(liquid):
- unanswered
highly soluble almost insoluble
Explain your answer from part (B) above. Check all that apply.
- unanswered
The components are both polar and therefore have the capability of mixing. The components are both polar and therefore they don't have the capability of mixing. The components are both nonpolar and therefore have the capability of mixing. The components are both nonpolar and therefore they don't have the capability of mixing. One component is polar and the other is nonpolar, and therefore they have the capability of mixing. One component is polar and the other is nonpolar, and therefore they don't have the capability of mixing. The components both have similar molecular weights and therefore have the capability of mixing. The components both have similar molecular weights and therefore they don't have the capability of mixing. One component has a much higher molecular weight than the other, and therefore they have the capability of mixing. One component has a much higher molecular weight than the other, and therefore they don't have the capability of mixing. The components are both liquid at room temperature and therefore have the capability of mixing. The components are both liquid at room temperature and therefore they don't have the capability of mixing. The components both lack hydrogen bonding, and therefore have the capability of mixing. The components both lack hydrogen bonding, and therefore they don't have the capability of mixing. One component has hydrogen bonding, while the other lacks it; therefore, they have the capability of mixing. One component has hydrogen bonding, while the other lacks it; therefore, they don't have the capability of mixing.
3 answers
I2 dissolves easily in CCl4. Both are covalent compounds.
"The components are both nonpolar and therefore have the capability of mixing."
B.
Almost insoluble.
"One component is polar and the other is nonpolar, and therefore they don't have the capability of mixing."
sorry the text garbage..
a,b,c were correct while
"One component is polar and the other is nonpolar, and therefore they don't have the capability of mixing."
just thought you wanted to know, thank you again