Where are you with this one?
Convert mass CO2 to mass C.
Convert mass H2O to mass H(atoms).
1.0g - mass C - mass H = mass O
Convert g C to mols.
Convert g H to mols
Convert g O to mols.
Find the ratio for the empirical formula.
Then (emprical formula) x number = molar mass. Solve for number (rounded to whole number).
Then (empirical formula)n = molecular formula.
Combustion analysis of 1.0g of a compound containing carbon , hydrogen and oxygen gives 2.3 g of carbon dioxide and 0.93g of water . If The relative molecular mass is 58. Calculate The empirical and molecular formula
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