Combined, there are 184
Asians, Africans, Europeans, and Americans in a village.The number of Asians exceeds the number of Africans and Europeans by 61. The difference between the number of Europeans and Americans is 11. If the number of Africans is doubled, their population exceeds the number of Europeans and Americans by 15.
Determine the number of Asians, Africans, Europeans, and Americans in this village.
So how many Asians:
Africans:
Europeans:
Americans in Village:
If i create this formula,
Assign letters to each race. These are your variables.
Asians = A
Africans = F
Europeans = E
Americans = M
A + F + E + M = 184
Is this a good way to start the problem?
You are told the number of Asians exceeds the number of Africans and Europeans by 61.
Therefore A - 61 = F + E
Kind of not sure where to go from here.
1 answer
A + F + E + M = 184
A - F - E + 0M = 61
0A + 0F + E - M = 11
2A + 0F -E - M = 15
There are several methods, including row reduction.