Combine the radicals using addition and subtraction. Give the answer in simplest radical form.

4√396 + √44 - 2√275

1 answer

To combine the radicals in the expression \( 4\sqrt{396} + \sqrt{44} - 2\sqrt{275} \), we will simplify each radical first:

  1. Simplifying \( \sqrt{396} \):

    To simplify \( \sqrt{396} \):

    • Break down \( 396 \) into its prime factors: \[ 396 = 4 \times 99 = 4 \times 9 \times 11 = 36 \times 11. \]
    • Thus, \( \sqrt{396} = \sqrt{36 \times 11} = \sqrt{36} \times \sqrt{11} = 6\sqrt{11} \).
    • Therefore, \( 4\sqrt{396} = 4 \times 6\sqrt{11} = 24\sqrt{11} \).
  2. Simplifying \( \sqrt{44} \):

    To simplify \( \sqrt{44} \):

    • Break down \( 44 \): \[ 44 = 4 \times 11. \]
    • Therefore, \( \sqrt{44} = \sqrt{4 \times 11} = \sqrt{4} \times \sqrt{11} = 2\sqrt{11} \).
  3. Simplifying \( \sqrt{275} \):

    To simplify \( \sqrt{275} \):

    • Break down \( 275 \): \[ 275 = 25 \times 11. \]
    • Therefore, \( \sqrt{275} = \sqrt{25 \times 11} = \sqrt{25} \times \sqrt{11} = 5\sqrt{11} \).
    • Thus, \( -2\sqrt{275} = -2 \times 5\sqrt{11} = -10\sqrt{11} \).

Now, we can rewrite the entire expression:

\[ 4\sqrt{396} + \sqrt{44} - 2\sqrt{275} = 24\sqrt{11} + 2\sqrt{11} - 10\sqrt{11}. \]

Next, combine the terms involving \( \sqrt{11} \):

\[ (24 + 2 - 10)\sqrt{11} = 16\sqrt{11}. \]

Thus, the final simplified form of the expression is:

\[ \boxed{16\sqrt{11}}. \]