did you mean:
log √(x+1) + 9logx ??
then
= log √(x+1) + log x^9
= log ( x^9 √(x+1) )
Combine into one log:
log
√
x + 1
+ 9 log x
i.e. rewrite as an expression of the form log u, where u is a function of x.
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