4 of 54 of 5 Items
Question
A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)
Responses
7.5 N
7.5 N
0.01 N
0.01 N
1 N
1 N
6.5 N
1 answer
To find the force exerted by the floor on the south end of the court, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a):
\[ F = m \cdot a \]
In this case, the mass of the tennis ball is 0.1 kg, and the acceleration is given as 10 m/s². Now plug in the values:
\[ F = 0.1 , \text{kg} \cdot 10 , \text{m/s}^2 = 1 , \text{N} \]
So, the force exerted by the floor on the ball is:
1 N
Thus, the correct response is 1 N.
