If the rod has a measurable radius, it is a cylinder.
The moment of inertia of cylinder about the axis passing through its center
is
I=mR²/2=mD²/8 = 5•10⁻⁴•0.3²/8 =…
College Physics- Inertia?
Find the moment of inertia about each of the following axes for a rod that is 0.300 in diameter and 1.60 long, with a mass of 5.00×10−2 .
How do you find this ? I know how to find the perpendicular and end .
but this?
About an axis along the length of the rod.
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