Question
Cole rewrote a quadratic function in vertex form.
h(x) = x²-6x+7
Step 1: h (x) = (x²-6x+)+7
Step 2: h (x) = (x²-6x+9)+7-9
Step 3: h (x) = (x-3)²+2
Cole said that the vertex is (3, 2). Is Cole correct? If not, identify the step in which Cole made the mistake and correct his work.
h(x) = x²-6x+7
Step 1: h (x) = (x²-6x+)+7
Step 2: h (x) = (x²-6x+9)+7-9
Step 3: h (x) = (x-3)²+2
Cole said that the vertex is (3, 2). Is Cole correct? If not, identify the step in which Cole made the mistake and correct his work.
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