Ask a New Question
Search
Cole rewrote a quadratic function in vertex form. h(x)=x^2 -6 +7
1 answer
h(x) = (x - 3)^2 - 2
Ask a New Question
or
answer this question
.
Similar Questions
Cole rewrote a quadratic function in vertex form. h(x)=x^2 -6x+7
Cole said that the vertex is (3, 2). Is Cole correct? If not,
1 answer
Cole rewrote the quadratic function h(x) = x^2 - 6x +7 into vertex form, Cole said the vertex is (3.2) is he correct? Show your
3 answers
Cole rewrote a quadratic function in vertex form.
h(x)= x2−6x+7 Step 1: h(x)= (x2−6x+ 9 )+7 Step 2: h(x)=(x2−6x+ 9 )+7 −9
1 answer
April rewrote a quadratic function in vertex form.
h(x)=5^2-30x+30 step 1 h(x)=5(x^2-6x+ )+30 step 2 h(x)=5(x^2-6x+9)+30-45 step
2 answers
more similar questions