A. en has 2 for a total of 4+ 2 more for each NH4. Coordination number is 6.
B. You have two ligands in en and 2 more for NH3 for a total of 4.
C. en is neutral. So is NH3. The charge on the complex ion is +3. So the oxidation state of Co is ???
[Co(NH3)2(en)2]^+3
what is the
A)coordination no.
B)no. of ligands
C)Oxidation state of Co
3 answers
O.N on co will be +3
O.N of Co will be +3