To balance the equation, it is already balanced:
CO + 2H2 → CH3OH
To convert 360 g CH3OH to mols CH3OH, use the molar mass of CH3OH:
mols CH3OH = 360 g CH3OH / 32.04 g/mol CH3OH = 11.25 mols CH3OH
To convert mols CH3OH to mols CO and mols H2, use the coefficients in the balanced equation:
mols CO = 11.25 mols CH3OH / 1 mol CO = 11.25 mols CO
mols H2 = 11.25 mols CH3OH / 2 mols H2 = 5.625 mols H2
Therefore, 11.25 mols CO and 5.625 mols H2 are needed to produce 360 g CH3OH.
CO + 2*H2 --> CH3OH
How many moles of each reactant are needed to produce 3.60 x 10^2g CH3OH?
I appreciate anyone who helps me with this. Also, please say the steps on how you got your answer.
Balance the equation. I think it is balanced.
Convert 360 g CH3OH to mols CH3OH.
mols = g/molar mass CH3OH.
Use the coefficients in the balanced equation to convert mols CH3OH to mols CO and do a separate one to convert to mols H2.
Post your work if you get stuck but explain what you don't understand.
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