It works the same way as stoichiometry.
1.
0.458 x 1/3 = ?
2.
Same process as in #1.
ClO3^-(aq)+3SO3^2- ¡÷ Cl^-(aq)+3SO4^2-
1) If the SO3^2- ion is disaapearing at rate of 0.458 mol/L*s, how fast is the Cl^- ion appearing?
2) if the after 10 minutes of reaction time, 1.09x10^-4 mole of Cl^- ion has been produced, how many moles of SO3^2- ion have been used up?
Please help I'm stuck with these 2 questions.
3 answers
@DrBob222 for number 2, is it 1.09x10^-4*1/3?
No, of course not.
#1. sulfite disappearance = 0.458 mol/L*s so
0.458 mol/L*s So3^2- x (1 mol Cl^-/3 mols So3^3-) = ?
So #2 must be what. Make those units cancel to come up with the unit you want.
#1. sulfite disappearance = 0.458 mol/L*s so
0.458 mol/L*s So3^2- x (1 mol Cl^-/3 mols So3^3-) = ?
So #2 must be what. Make those units cancel to come up with the unit you want.
1 answer