time of flight ... t = √(2 h / g)
min horiz vel = 9.19 m / t
Cliff divers at Acapulco jump into the sea
from a cliff 30.1 m high. At the level of the
sea, a rock sticks out a horizontal distance of
9.19 m.
The acceleration of gravity is 9.8 m/s
With what minimum horizontal velocity
must the cliff divers leave the top of the cliff if
they are to miss the rock?
Answer in units of m/s.
1 answer
1 answer