Let \( x \) be the total restaurant bill. The 20% tip on the bill can be calculated as \( 0.20x \).
Clay's total expenses would then be the bill amount plus the tip, which can be expressed as:
\[ x + 0.20x = 1.20x \]
Clay has $60.00, which means he can afford a total of $60.00 for both the bill and the tip. Therefore, we set up the following equation:
\[ 1.20x \leq 60 \]
To find the maximum bill total \( x \), we can solve for \( x \):
\[ x \leq \frac{60}{1.20} \]
Calculating the right side:
\[ \frac{60}{1.20} = 50 \]
Thus, the maximum total bill that Clay can afford in order to leave a 20% tip is:
\[ x \leq 50 \]
Therefore, Clay can leave a 20% tip on a restaurant bill of \( \boxed{50} \).