To find the width \( w \) of the cabinet using the volume formula \( V = lwh \), we need to rearrange the formula to isolate \( w \).
Starting with the original volume formula:
\[ V = lwh \]
To isolate \( w \), we divide both sides of the equation by \( lh \):
\[ w = \frac{V}{lh} \]
Now we can substitute the known values to find \( w \). We know:
- \( V = 60 , \text{ft}^3 \)
- \( l = 4 , \text{ft} \)
- \( h = 5 , \text{ft} \)
Plugging these values into the formula gives:
\[ w = \frac{60 , \text{ft}^3}{(4 , \text{ft})(5 , \text{ft})} \]
Calculating the denominator:
\[ (4 , \text{ft})(5 , \text{ft}) = 20 , \text{ft}^2 \]
Now compute \( w \):
\[ w = \frac{60 , \text{ft}^3}{20 , \text{ft}^2} = 3 , \text{ft} \]
Thus, the width \( w \) of the cabinet is:
\[ w = \frac{60}{4 \cdot 5} \]
So, the rearranged formula is:
\[ w = \frac{V}{lh} \]