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Question Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and...Question
Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volume is 60 ft.^3 . They need to know the width of the cabinet to make sure that it will fit in the space where they want to put it. Using the volume formula, V=lwh , rearrange the formula to highlight the quantity of interest. Note that volume is represented with a capital V in the formula
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GPT-4o mini
To find the width (w) of the cabinet using the volume formula, we start with the formula for volume:
\[ V = l \cdot w \cdot h \]
Where:
- \( V \) is the volume,
- \( l \) is the length,
- \( w \) is the width,
- \( h \) is the height.
We are given:
- \( V = 60 \, \text{ft}^3 \)
- \( l = 4 \, \text{ft} \)
- \( h = 5 \, \text{ft} \)
We want to rearrange the formula to solve for the width \( w \). We can do this by isolating \( w \) on one side of the equation.
Starting with the original equation:
\[ V = l \cdot w \cdot h \]
We can divide both sides by \( l \cdot h \):
\[ w = \frac{V}{l \cdot h} \]
Now substituting in the values for \( V \), \( l \), and \( h \):
\[ w = \frac{60 \, \text{ft}^3}{4 \, \text{ft} \cdot 5 \, \text{ft}} \]
Calculating the denominator:
\[ 4 \, \text{ft} \cdot 5 \, \text{ft} = 20 \, \text{ft}^2 \]
Now substituting that back into the equation for \( w \):
\[ w = \frac{60 \, \text{ft}^3}{20 \, \text{ft}^2} \]
Calculating \( w \):
\[ w = 3 \, \text{ft} \]
Thus, the width of the cabinet is **3 ft**.
\[ V = l \cdot w \cdot h \]
Where:
- \( V \) is the volume,
- \( l \) is the length,
- \( w \) is the width,
- \( h \) is the height.
We are given:
- \( V = 60 \, \text{ft}^3 \)
- \( l = 4 \, \text{ft} \)
- \( h = 5 \, \text{ft} \)
We want to rearrange the formula to solve for the width \( w \). We can do this by isolating \( w \) on one side of the equation.
Starting with the original equation:
\[ V = l \cdot w \cdot h \]
We can divide both sides by \( l \cdot h \):
\[ w = \frac{V}{l \cdot h} \]
Now substituting in the values for \( V \), \( l \), and \( h \):
\[ w = \frac{60 \, \text{ft}^3}{4 \, \text{ft} \cdot 5 \, \text{ft}} \]
Calculating the denominator:
\[ 4 \, \text{ft} \cdot 5 \, \text{ft} = 20 \, \text{ft}^2 \]
Now substituting that back into the equation for \( w \):
\[ w = \frac{60 \, \text{ft}^3}{20 \, \text{ft}^2} \]
Calculating \( w \):
\[ w = 3 \, \text{ft} \]
Thus, the width of the cabinet is **3 ft**.
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