The given system of equations is:
4x + 10y = 40
2x + 5y = 40
We can solve this system using any method such as substitution, elimination, or matrix algebra. Let's solve it using the elimination method:
Multiply the second equation by 2 to make the coefficients of x in both equations equal:
4x + 10y = 40
4x + 10y = 80
Now subtract the first equation from the second equation:
(4x + 10y) - (4x + 10y) = 80 - 40
0 = 40
This equation, 0 = 40, is not true. It implies that there is no solution to the system of equations. Therefore, the given system of equations does not have any solutions.
Classify the systems of equations based on the number of solutions they have.
4x + 10y = 40
2x + 5y = 40
1 answer
1 answer