To analyze the situation described, we need to calculate the number of boxes packaged over the specified time periods.
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For the first 3 hours: The company packs 80 boxes per hour.
- Boxes packed in first 3 hours = \(80 \text{ boxes/hour} \times 3 \text{ hours} = 240 \text{ boxes}\)
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For the next 2 hours: There is no packaging during the training session.
- Boxes packed = 0 during this period.
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For the next 4 hours: The company packs 20 boxes per hour.
- Boxes packed in the next 4 hours = \(20 \text{ boxes/hour} \times 4 \text{ hours} = 80 \text{ boxes}\)
Now we can sum the total number of boxes packed by the end of each time frame:
- After 3 hours: 240 boxes
- After 5 hours (3 hours of packing + 2 hours of training): 240 boxes (no change)
- After 9 hours (5 hours from the previous period + 4 hours of packing): \(240 + 80 = 320 \text{ boxes}\)
Now we can determine the points for our piecewise function:
- Starting point: (0, 0) (at the start, no boxes packed yet)
- After 3 hours: (3, 240)
- After 5 hours: (5, 240) (still 240 boxes due to break)
- After 9 hours: (9, 320)
Based on the calculations, the piecewise function has points (0, 0), (3, 240), (5, 240), and (9, 320).
Now we can compare our results to the options provided:
- Option A: (0, 0), (3, 240), (5, 240), (9, 280) – Incorrect, last point is wrong.
- Option B: (0, 0), (3, 240), (5, 240), (9, 320) – Correct.
- Option C: (0, 0), (3, 240), (7, 320), (9, 320) – Incorrect, misrepresents the timing.
- Option D: (0, 0), (4, 60), (6, 60), (9, 320) – Incorrect points.
Therefore, the correct answer is B.