Claculate the voltage of the following cell at 25 Degress Celcius.

Question

2Ag (aq) (0.010M) + Cu(s) -> Cu^2(aq)(0.1M) +2Ag(s)

Answer 1

E Ag = EoAg -(0.0592/1)*log(1/0.01) = ?
E Cu = EoCu -(0.0592/2)*log(1/0.1) = ? then change the sign.
Add the two final values for Ecell.