Circle C has its center at (9,0) and a point is on the circle at A(8,6).

Question

Which answer verifies whether point P(10,−7) lies on the circle?

a. The statement (9−0)2+(8−6)2≠(9−0)2+(10+7)2 is a true statement, so P is not on ⨀C.
b. The equation (9−0)2+(8−6)2=(9−0)2+(10+7)2 is a true statement, so P is on ⨀C.
c. The statement (9−8)2+(0−6)2≠(9−10)2+(0+7)2 is a true statement, so P is not on ⨀C.
d. The equation (9−8)2+(0−6)2=(9−10)2+(0+7)2 is a true statement, so P is on ⨀C.

Answer 1

This question is a good example of how to make a rather simple concept look complicated

centre is ( 9,0) , so equation is
(x-9)^2 + y^2 = r^2
point (8,6) is on it, then 1^2 + 6^2 = r^2 = 37

the circle is : (x-9)^2 + y^2 = 37

Now sub in P(10,−7)
If it satisfies the equation P is on the circle
If it does not satisfy the equation P is not on the circle

Answer 2

I think it is on the line is the answer B?

Answer 3

from where did the 37 came from?