Chuck a luck is a game where each of the 3 dice has 6 possible outcomes (1, 2, 3, 4, 5, or 6) and there are a total of 6^3 = 216 possible outcomes when the dice are tumbled.
To find the probability that none of the dice will show a 5, we need to determine the number of outcomes in which none of the dice show a 5.
Since each die has 5 possible outcomes that are not 5 (1, 2, 3, 4, or 6), there are 5^3 = 125 outcomes in which none of the dice show a 5.
Therefore, the probability that none of the dice will show a 5 is 125/216, which can be simplified to approximately 0.579 or 57.9%.
Chuck a luck is a game of chance in which 3 dice in a cage are tumbled. Bets can be placed on the values that the 3 dice will show. Find the probability that none of the dice will show a 5
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