Asked by Chamel
Chromium is reduced from CrO4{2-} to Cr(OH)4- in an electrolytic cell. What mass of Cr(OH)4- is formed by passage of 4.50 A for a period of 8000 seconds?
Answers
Answered by
bobpursley
Isn't an amp a coulomb of electrons?
number electrons=1coulomb/charge on each electron
Now, after you figure that out, multiply it by 4.5*8000 to get the number of electrons.
Thence, divide it by avagradros number to convert it to moles of electrons.
It appears the chronium went from +6 to +5, or each ion taking on one electron.
That number of moles of electrons is the same number of moles of CrO4 -2 ions, so what is the mass of that?
number electrons=1coulomb/charge on each electron
Now, after you figure that out, multiply it by 4.5*8000 to get the number of electrons.
Thence, divide it by avagradros number to convert it to moles of electrons.
It appears the chronium went from +6 to +5, or each ion taking on one electron.
That number of moles of electrons is the same number of moles of CrO4 -2 ions, so what is the mass of that?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.