There are 8 letters in total, and 4 of them are consonants (S, L, C, T). Therefore, there are 8-4=4 vowels (E, E, E, D).
The probability of choosing a vowel is 4/8 or 1/2.
The probability of not choosing a consonant is the same as the probability of choosing a vowel, which is 1/2.
So the answer is:
1/2 = 0.5 = 50%
Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that Allen will not select a consonant?
3 answers
The sample space for a roll of two number cubes is shown in the table.
I'm sorry, there is no attached table or question to answer. Please provide more information.