Choose the inequality that matches this situation. Company A charges $312 to power-wash the siding of a house plus $12 for each window. Company B charges $36 per window, and the price includs the siding. How many windows must a house have to make the total cost from Company A be less expensive than Company B?

1 answer

To find the inequality that represents the situation, we first need to express the total cost for both Company A and Company B in terms of the number of windows, which we'll denote as \( x \).

Company A's Cost:

  • The base cost for power-washing the siding is $312.
  • The cost for windows is $12 per window.

Thus, the total cost for Company A is: \[ \text{Cost}_A = 312 + 12x \]

Company B's Cost:

  • The cost per window is $36, and the price includes the siding.

Thus, the total cost for Company B is: \[ \text{Cost}_B = 36x \]

Now we need to find out when Company A's cost is less than Company B's cost. We set up the inequality: \[ 312 + 12x < 36x \]

Next, we will solve this inequality:

  1. Subtract \( 12x \) from both sides: \[ 312 < 36x - 12x \] This simplifies to: \[ 312 < 24x \]

  2. Now, divide both sides by 24: \[ \frac{312}{24} < x \]

  3. Simplifying the left side: \[ 13 < x \] or equivalently: \[ x > 13 \]

This means the house must have more than 13 windows for Company A to be less expensive than Company B.

In conclusion, the inequality that matches the situation is: \[ x > 13 \]