4y(8y+24)^ - 1 ,using the property that a^-x = 1/a^x
= 4y/(8y+24)
= 4y/(4(2y + 6) )
= y/(2y + 6)
or
y/(2(x+3)), since the denominator cannot be zero, x+3≠0 ----> x ≠ -3
Choose the correct rewriting of this algebraic fraction and give the exclusion represented by your choice.
4y(8y+24)^ - 1 : 2y/2y+3 OR y/(2)(y+3)?
y ≠ : +3 OR -3 ?
3 answers
Great, thank you so much! :)
Algebraic fraction simplify 8/y+4y