It takes 55 moles of C to use up each mole of Mg.
So, how many moles of Mg is 4.5g?
Chlorophyll, the green pigment in leaves, has the formula C55H72MgN4O5. If 4.5g of Mg is available to a plant for chlorophyll synthesis, how many grams of carbon will be required to completely use up the magnesium? (enter only your numeric answer, not in scientific notation, and with 1 decimal place)
3 answers
mm = molar mass
am = atomic mass
4.5 g Mg x (mm C55H72MgN4O5/am Mg)*55 = g C
am = atomic mass
4.5 g Mg x (mm C55H72MgN4O5/am Mg)*55 = g C
oops. My solution needs work. I left out a step. It should be this.
4.5 g Mg x (mm C55H72MgN4O5/am Mg) x (55/mm C55H72MgN4O5) x 12 = grams Carbon.
A shorter solution is 4.5 g Mg x (55*am C/am Mg) = grams carbon. Sorry about that.
4.5 g Mg x (mm C55H72MgN4O5/am Mg) x (55/mm C55H72MgN4O5) x 12 = grams Carbon.
A shorter solution is 4.5 g Mg x (55*am C/am Mg) = grams carbon. Sorry about that.