Chin went to a store where he spent one half of his money and$14 more.He then went to another store where he spent one third of his money and $14 more. If he then had no money left, how much did he have when he entered the first store?

Answer 1

money spent in first store = (1/2)x + 14
money spent in 2nd store = (1/3)x + 14

so (1/2)x + 14 + (1/3)x + 14 =x
times 6 , the LCD, to clear fractions

3x + 84 + 2x + 84 = 6x
x = 168

check:
amount spent in store 1 = 84 + 14 = 98
money spent in store 2 = 56+14 =70
he spent 98+70 = 168

Answer 2

Nicely done

Answer 3

Remaining Money (y) from the first store is x - 1/2x +14
The Money spent in the second store is 1/3y + 14

So solving for initial money value gives us $70