To determine whether the graph accurately represents the given piecewise function, we should analyze the function:
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For \(1 < x \leq 3\): The dosage is a constant \(0.5\). This segment of the function should show a horizontal line at \(y = 0.5\) from just above \(x = 1\) to \(x = 3\) including \(3\) (closed circle).
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For \(3 < x \leq 6\): The dosage here is \(1.0\). This segment also shows a horizontal line at \(y = 1.0\) from just above \(x = 3\) to \(x = 6\) including \(6\) (closed circle).
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For \(x > 6\): The formula is \(0.5x\), which is a linear function. This would mean the graph increases from the point where \(x > 6\) (open circle at \(6\) since this part does not include \(x = 6\)).
Now, let's analyze the options provided regarding the accuracy of the graph representing the piecewise function:
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No. The graph should be continuous, with all the pieces connected. This is not correct as piecewise functions can have breaks.
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Yes. The graph is correct because all three pieces of the function are present. This might not necessarily be true if the connection between segments (especially regarding closed/open circles) is not accurate.
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Yes, because all of the points at the ends of the pieces of the function should have closed circles. This is inaccurate. The boundaries at \(x = 3\) and \(x = 6\) are treated differently (closed at \(3\), open at \(6\)).
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No. There should be an open circle on the first point of two parts of the function. This seems most accurate. There should indeed be an open circle at \(x=3\) where the first piece ends and the second begins, indicating the transition from the first piece to the second piece.
Therefore, the best answer is:
- No. There should be an open circle on the first point of two parts of the function.