Question

Children sled down a 45 m long hill inclined at 26 degrees. At the bottom, the slope levels out. If the coefficient of friction is 0.1, how far do the children slide on the level ground?

Answer 1

s₁=45 m
α=26⁰
s₂=?

ΔPE +W(fr)₁ =KE =W(fr)₂,
ΔPE +W(fr)₁ =W(fr)₂,
mgh+ F(fr)₁•s₁ = F(fr)₂•s₂.

h=s₁•sinα,
F(fr)₁ =μ•N₁=μ•mgcosα,
F(fr)₂ =μ•N₂=μ•mg,

mgs₁sinα + μ•mgcosα•s ₁ = μ•mg s₂,
s₁•sinα + μ•cosα•s ₁ = μ•s₂,

s₂=(s₁•sinα + μ•cosα•s ₁)/μ =…