Children sled down a 45 m long hill inclined at 26 degrees. At the bottom, the slope levels out. If the coefficient of friction is 0.1, how far do the children slide on the level ground?

1 answer

s₁=45 m
α=26⁰
s₂=?

ΔPE +W(fr)₁ =KE =W(fr)₂,
ΔPE +W(fr)₁ =W(fr)₂,
mgh+ F(fr)₁•s₁ = F(fr)₂•s₂.

h=s₁•sinα,
F(fr)₁ =μ•N₁=μ•mgcosα,
F(fr)₂ =μ•N₂=μ•mg,

mgs₁sinα + μ•mgcosα•s ₁ = μ•mg s₂,
s₁•sinα + μ•cosα•s ₁ = μ•s₂,

s₂=(s₁•sinα + μ•cosα•s ₁)/μ =…