Asked by Anonymous

Chester makes 1L of a 0.01M HCl solution and measure the pH. Burt then adds 5.80 g of sodium chloride
to Chester’s solution and measures the pH. Calculate the difference between the two pH values
obtained.

Answers

Answered by DrBob222
This is not a simple question.
1. Use the Debye-Huckel relationship to calculate the pH of 0.01M HCl. That is not the simple pH = -log(0.01) = 2

2. Now do the same for the mixture of 0.01M HCl and 5.80g NaCl after converting NaCl to mols then to M.

3. Solve for delta pH.
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