Chemical analysis of a silicon crystal reveals gallium at a level of 3.091X10^-2 atomic percent. Assuming that the concentration of thermally excited charge carriers from the Si matrix is negligible, what is the density of free charge carriers (free carriers/cm3) in this Si crystal?
18 answers
1.598e14.
an explanation please?
i need a formula!
i need a formula!
The answer is not right, at least for me. anyone who knows how to do it and could write how ?
Please, I need the formula!
The answer 1.598e14 was not right for me too. Any ideas what happen and how to write it out?
What is the formula to use
Please, I need the formula!
The data for everyone of us is different as you noticed formula is required
Go to back to H4P2
As its Si: 5.00*10^22 / (gallium level*10^-2) by someguy
1.5455*10^19
gallium level*10^-2) what is this?
What is the formula, please?
What about 3.091*10^-7? please
H4P2
1.6265*10^14 i have the answer for 3.091*10^-7
here the caculation
atomic percent*NA(avogadro number)
the solution/atomic volume of gallium
here the caculation
atomic percent*NA(avogadro number)
the solution/atomic volume of gallium
1.5442*10^14
this is the corect ones
this is the corect ones
step1
(6.023*10^23)/(12.05)=m
step 2
m*(level of atomic percent)*(10^-2)
(6.023*10^23)/(12.05)=m
step 2
m*(level of atomic percent)*(10^-2)