check my answer please find the number of zeros(x-intercepts) y=3k^3-6k^2-45k=k(3k+9)(k-5)= k(3k^2-15k+9k-45)=k(3k^2-6k-45) or should i do it 3k(k-5) (k+3)=3k(k^2+3k-5k-15)=3k(k^2-2k-15) which on is the right one please let me know.thanks

Question

check my answer please find the number of zeros(x-intercepts) y=3k^3-6k^2-45k=k(3k+9)(k-5)= k(3k^2-15k+9k-45)=k(3k^2-6k-45)                              or should i do it 3k(k-5) (k+3)=3k(k^2+3k-5k-15)=3k(k^2-2k-15) which on is the right one please let me know.thanks

Mac · Answer

Yes you factor 3k(k-5)(k+3) and your check says you did it correctly Now to find the zeros Set each factor = 0. And solve 3k=0. K=0 K-5=0. K=5 K+3=0. K=-3