Check if im right please:

Question

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) At a specific time in the reaction, ammonia is disappearing at rate of 0.068 mol/(L • s). What is the corresponding rate of production of water?

I did
Rate of Production H20 = 1/6(0.068)
= 0.0113 mol/(L*s)

Am i right?>

Answer 1

I would have done it this way/.
0.068 x *6 mols H2O x 4 mols NH3) = 0.068 x 6/4 = ?