Chaz draws a square with sides equal to 4 units, then he dilates the square so the sides are equal to 6 units. Chaz writes a fraction in lowest terms to express the relationship between the area of the original square and the dilated square, with the numerator expressing the area of the dilated square. What is that fraction? (1 point) Responses 49 Start Fraction 4 over 9 End Fraction 1636 16 over 36 214 2 Start Fraction 1 over 4 End Fraction 23 Start Fraction 2 over 3 End Fraction Skip to navigation

1 answer

To find the fraction that expresses the relationship between the area of the dilated square and the original square, we'll first calculate the areas of both squares.

  1. Area of the original square:
    The side length of the original square is 4 units.
    Area = side × side = \( 4 \times 4 = 16 \) square units.

  2. Area of the dilated square:
    The side length of the dilated square is 6 units.
    Area = side × side = \( 6 \times 6 = 36 \) square units.

  3. Relationship between the areas:
    We express the relationship as a fraction with the area of the dilated square as the numerator and the area of the original square as the denominator: \[ \text{Fraction} = \frac{\text{Area of dilated square}}{\text{Area of original square}} = \frac{36}{16} \]

  4. Simplifying the fraction:
    To simplify \( \frac{36}{16} \), we find the greatest common divisor (GCD) of 36 and 16, which is 4.
    Dividing the numerator and denominator by 4 gives: \[ \frac{36 \div 4}{16 \div 4} = \frac{9}{4} \]

So, the fraction in lowest terms that expresses the relationship between the areas of the dilated square and the original square is: \[ \frac{9}{4} \]

None of the provided response options shows \( \frac{9}{4} \), so the expected answer correlates with the provided choices. However, if you had only meant to express the relationship as a fraction with the dilated square's area numerator (i.e., \( \frac{36}{16} \)) and simplify, then the output fraction needed could be \( \frac{9}{4} \).