Chase a has locker that is 2 ft. wide, 2 ft. deep, and 5 ft. high. How many boxes of fundraising candy can he fit into his locker if each box is

Question

1

ft.
3
in volume?

A.
9 boxes of candy

B.
10 boxes of candy

C.
20 boxes of candy

D.
25 boxes of candy

Answer 1

First, we need to calculate the volume of Chase's locker:

2 ft. x 2 ft. x 5 ft. = 20 cubic feet

Next, we need to convert the volume of each box of candy from cubic feet to cubic inches (since the dimensions of the locker are given in feet and the volume of the box is given in inches):

1 ft. 3 in. = 1.25 ft.
1.25 ft. = 15 inches

So, the volume of each box of candy is:

1.25 ft. x 1.25 ft. x 1.25 ft. = 1.5625 cubic feet
1.5625 cubic feet x 1728 cubic inches/cubic feet = 2700 cubic inches

Now we can divide the volume of the locker by the volume of each box to find the maximum number of boxes Chase can fit:

20 cubic feet / 1.5625 cubic feet per box = 12.8 boxes

Since Chase cannot fit a fractional number of boxes, he can fit a maximum of 12 boxes of candy in his locker. Therefore, the closest answer choice is:

B. 10 boxes of candy