Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother. Charlie has $27. How much can he spend on each sandwich if they are all the same price?


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The inequality representing how much Charlie can spend is
Charlie can spend
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3 answers

To determine how much Charlie can spend on each sandwich, we first need to set up the relationship between his budget and his purchases. Charlie has a total budget of $27.

He is going to buy 6 sandwiches and 1 kid's meal for $3.

  1. Subtract the cost of the kid's meal from his total budget:
    Total budget = $27
    Cost of kid's meal = $3
    Remaining budget for sandwiches = $27 - $3 = $24

  2. Let \( x \) be the price of each sandwich.
    Since Charlie is buying 6 sandwiches, the total cost for the sandwiches can be expressed as \( 6x \).

  3. Set up the inequality:
    The total cost of the sandwiches must be less than or equal to his remaining budget: \[ 6x \leq 24 \]

  4. Solve for \( x \): To find out how much he can spend on each sandwich, divide both sides of the inequality by 6: \[ x \leq \frac{24}{6} \] \[ x \leq 4 \]

Therefore, Charlie can spend $4 or less on each sandwich.

In summary, the inequality representing how much Charlie can spend is: \[ 6x \leq 24 \] which means Charlie can spend $4 or less on each sandwich.

The inequality representing how much Charlie can spend is
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^
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6x+ 3≤27

6x+3≥27

3x+6≥27

3x+6<27

The correct inequality representing how much Charlie can spend is:

\[ 6x + 3 \leq 27 \]

Here's the breakdown:

  • \( 6x \): represents the total cost of the 6 sandwiches, where \( x \) is the price of each sandwich.
  • \( 3 \): represents the cost of the kid's meal.
  • \( 27 \): is Charlie's total budget.

So, the inequality \( 6x + 3 \leq 27 \) captures the relationship correctly, indicating that the total cost of the sandwiches plus the kid's meal should not exceed Charlie's budget.

Therefore, the first option \( 6x + 3 \leq 27 \) is the correct choice.