Since Charlie's device is marked in half-millimetres, his measurement will be 3.75 cm.
To determine the uncertainty in his measurement, we need to consider the smallest unit marked on his device, which is half-millimetre or 0.05 cm. The uncertainty will be half of this smallest unit, so the uncertainty in Charlie's measurement will be 0.025 cm.
Therefore, Charlie will record his measurement as 3.75 cm ± 0.025 cm.
. Charlie is measuring a piece of equipment that he is using in an electrical repair. The true length of the piece is 3.749 cm. Charlie is using a device marked in half-millimetres. What
measurement and uncertainty will he record?
1 answer
1 answer