charges of +1.000 C are located at the corners of a 45-45- right triangle which has a hypotenuse that is 1.414 m long. Determine the resultant force on the charge located at the vertex of the right angle.

Answer 1

The two charges at the 45 degree corners are each 1.0 m from the charge at the right angle.

There are two perpendicular forces acting on the right angle vertex charge. Each has magnitude
k Q^2/(1.0m^2)
where Q = 1.0C and k is the Coulomb constant. (look it up)

Add thse two forces as vectors. The magnitude should be sqrt2 * the magnitude of the individual forces. The direction will be along the bisector of the right angle.