To balance the skeleton equation:
\[ __ \text{NaCl} + __ \text{CaO} \rightarrow __ \text{Na}_2\text{O} + __ \text{CaCl}_2 \]
we can assign coefficients to each compound:
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Start with sodium (Na). There are 2 Na in \(\text{Na}_2\text{O}\), so we need 2 NaCl: \[ 2 \text{NaCl} \]
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For calcium (Ca), there is 1 in \(\text{CaO}\) and 1 in \(\text{CaCl}_2\), so we need 1 \(\text{CaO}\): \[ 1 \text{CaO} \]
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For chloride (Cl), there are 2 in \(\text{CaCl}_2\), and we already have 2 NaCl giving us 2 Cl.
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For oxygen (O), there is 1 in \(\text{CaO}\) and 1 in \(\text{Na}_2\text{O}\), so we need 1 \(\text{Na}_2\text{O}\) to balance out: \[ 1 \text{Na}_2\text{O} \]
Now we can summarize the balanced equation: \[ 2 \text{NaCl} + 1 \text{CaO} \rightarrow 1 \text{Na}_2\text{O} + 1 \text{CaCl}_2 \]
Thus, the coefficients are: \[ 2, 1, 1, 1 \]
So the correct response is: 2, 1, 1, 1.