recall the basic definition of the logarithm:
b^(logb(x)) = x
logb(b^x) = x
5^x = 125
so, just take log5 of both sides:
log5(5^x) = log5(125)
x = log5(125)
Change the exponential statement 5^x=125 into an equivalent logarithmic statement.
I know the answer is log5(125)=(x)
Just don't know the steps to get it.
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