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Change the equation from standard form to slope-intercept form by solving for y.

11x-8y=-48

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To convert the equation \( 11x - 8y = -48 \) from standard form to slope-intercept form (which is \( y = mx + b \)), we need to solve for \( y \).

Starting with the equation:

\[ 11x - 8y = -48 \]

  1. First, isolate the term involving \( y \):

\[ -8y = -11x - 48 \]

  1. Next, divide every term by \(-8\) to solve for \( y \):

\[ y = \frac{-11x}{-8} + \frac{-48}{-8} \]

This simplifies to:

\[ y = \frac{11}{8}x + 6 \]

So the slope-intercept form of the equation is:

\[ y = \frac{11}{8}x + 6 \]

Here, the slope \( m \) is \( \frac{11}{8} \) and the y-intercept \( b \) is \( 6 \).