CH3COOH + C5H12O -> C7H14O2 + H2O

If the yield for the reaction is 45%, how many grams of the product are formed when 3.58 g of acetic acid are reacted with 4.75 grams of isopentyl alcohol?

Millimoles of acetic acid= 59.6667
Millimoles of isopentyl alcohol= 53.9773

How would I convert mmoles acetic acid to mmoles of the product and mmoles isopentyl alcohol to mmoles of the product?

Would I take the millimoles of each(acetic acid and isopentyl alcohol) and multiply that value by the molecular weight of the products (148 g/mol)?