Hmm..after drawing this I find that all I did to get the other structure was to flip the first or second structure horizontally and I got the same exact thing.
Based on this would they be constitutional isomers or represent the same compound?
CH3CHClCH2Cl vs. CH2ClCHClCH3
How would I know if :
-The two formulas represent different compounds which are constitutional isomers.
-The two formulas represent different compounds that are not isomeric.
-The two formulas represent the same compound.
~if they were isomers wouldn't that constitute placing the Cl in a different position and also having the same molecular formula?
But what does Isometric mean then?
I need help on this. Thank you =)
6 answers
The two structures you have drawn are the same compound. I can't do it on the board but if you will draw them on a sheet of paper something like this:
   H
   |
H-C-C- etc
   |
   H
you will see that all the question has done is draw the first compound backwards to make the second compound.
   H
   |
H-C-C- etc
   |
   H
you will see that all the question has done is draw the first compound backwards to make the second compound.
That is, the Cl on the right end of compound 1 is on the left end of compound 2. Compound 1 starts with a CH3 group and compound 2 ends with a CH3 group.
I was thinking that they were the same but wasn't sure since the examples in the program were only of flipping the structure vertically not horizontally and I wanted to be sure since I haven't done organic chem in a long time.
If it was a constitutional isomer wouldn't they have to have moved the Cl to let's say the top of the first carbon?
If it was a constitutional isomer wouldn't they have to have moved the Cl to let's say the top of the first carbon?
To make constitutional isomers of a dichloro propane, one structure will need a Cl on carbon 1 and another one on carbon 2. Another isomer would need to have a a Cl atom on C1 and another on C3. A third isomer would have both Cl atoms on C1. I THINK that is all of them.
Hm..I need to work on this from what you said since I only mentioned one isomer.
Thanks for all your help Dr.Bob =D
Thanks for all your help Dr.Bob =D